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4573 |
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Date: December 09, 2013 at 18:13:02
From: La Man, [DNS_Address]
Subject: Easy/fun (?) math problem for the panel (above my pay grade) |
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No tricks, but makes me brain hurt.
My daughter will turn 11 come January.
I recently turned 44.
That makes me for a time, precisely 4x older than her.
I cannot envision another age where we will end up with the same
multiple ergo a solid number (2x 3x 4x etc)
Is there a way to express that ie logarithmically or algebraically?
I was 34 when she was born. Obviously there's a fudge factor with
the birth months, but for a time I will be 4x.
Will this ever happen again at any multiple?
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Responses:
[4590] [4589] [4574] [4576] [4578] [4577] |
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4590 |
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Date: December 10, 2013 at 14:19:49
From: Skywise, [DNS_Address]
Subject: Re: Easy/fun (?) math problem for the panel (above my pay grade) |
URL: Twice as old--again! |
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I get slightly different answers than others, and it's due to the "fudge factor" you mentioned.
The long complex answer....
Twice as old... again.
http://www.math.brown.edu/~banchoff/twiceasold/
Brian
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4589 |
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Date: December 10, 2013 at 10:43:48
From: JTRIV, [DNS_Address]
Subject: Re: Easy/fun (?) math problem for the panel (above my pay grade) |
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Hi Mark
X = Y + 33
So the only multiples are when she is 11, now making you 4 times older and when she's 33 and your 66 making you 2 times older.
Cheers
Jim
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4574 |
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Date: December 09, 2013 at 19:55:08
From: dib, [DNS_Address]
Subject: Re: Easy/fun (?) math problem for the panel (above my pay grade) |
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You won't get a whole number over 4, because it's a declining ratio. You could get a 3, but missed by one at 16 and 17. That leaves only a multiple of 2 at 33-66. I didn't use a formula.
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Responses:
[4576] [4578] [4577] |
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4576 |
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Date: December 09, 2013 at 20:29:14
From: La Man, [DNS_Address]
Subject: Re: Easy/fun (?) math problem for the panel (above my pay grade) |
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Bitchin, thanks. Was just thinking if it would ever work for the 6
almost 7 year old or the 3 almost 4 year old. I guess working in
reverse works too, two years from now I will get me 45 the boy 5.
I guess I wonder mathematically why the ratio changes, ergo when
she was born I was 34, and was still 34 when she turned 1.
1/34=.029. 11/44 =.025. (Obviously the 4x).
10 years from now she's 21 me 54 , 21/54=.3888.
Just interested in why the percentage changes even though
the distance will always be the same
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Responses:
[4578] [4577] |
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4578 |
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Date: December 09, 2013 at 22:39:32
From: dib, [DNS_Address]
Subject: Re: Easy/fun (?) math problem for the panel (above my pay grade) |
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You brought up a couple of variables that I didn't think of. If your daughter was younger, then you could have a multiple over 4, but none hit on a whole number except that when she was one, you would have been 33 times as old. And also, unless you have the same birthday, then the bigger the distance between your birthdays, the more opportunities you have to hit on those multiples. The easiest way to calculate those whole number hits is to just make a side by side table, ie, 11-33, 12-34, 13-35, etc, and then checking for whole number multiples. The reason the percentages change is because your question raises your daughter's age by the multiplier you choose, ie, 2x, 3x, 4x, but your age is only going up 11 with each increase, a fraction of that multiple; eg, 2x of 11 is 22, but the equivalent in your age is 33+11. 3x of ll is 33 (triple), but your equivalent age only increased by 33+11+11+11 (double).
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4577 |
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Date: December 09, 2013 at 21:05:12
From: Karen in IL, [DNS_Address]
Subject: if we're all still here... |
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I think it's cool that when she's 33, you'll be 66...
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